Wednesday, February 08, 2006
Study Guide Chem Periodic and Naming Answers: Week 5
1. A
2. C
3. D
4. D
5. B
6. D
7. C
8. D
9. A
10. C
11. C
12. D
13. A
14. A
15. C
16. D
17. A
18. C
19. D
20. D
21. B
22. D
23. D
24. C
25. C
26. B
27. C
28. B
29. B
30. D
31. B
32. C
33. C
34. C
35. A
36. B
37. B
38. D
39. B
PROBLEM
40. 83.98 g/mol AlF3
26.98 g/mol Al + (3 ´ 19.00 g/mol F) = 89.3 g/mol AlF3
41. 101.96 g/mol Al2O3
(2 ´ 26.98 g/mol Al) + (3 ´ 16.00 g/mol O) = 101.96 g/mol Al2O3